The unit vector in the direction of the resultant of vectors a -2 -2 -5 k- and b -2 -3 k- isA- 4-29-3-29-2-29k-B- 4-29-3-29-2-29k-C- 4-29-3-29-2-29k-D- 4-29-3-29-2-29k-

The correct option is A a + b=(4,3, 2) a+b/ |a + b |= ( 4/√(29), 3/√(29), 2/√(29), ) ...

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Byju's Answer

Standard XII

Mathematics

Applications of Cross Product

The unit vect...

Question

The unit vector in the direction of the resultant of vectors $\to a = 2^i + 2^j - 5^k a n d \to b = 2^i +^j + 3^k$ is

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Solution

The correct option is B

$\to a + \to b = (4, 3, - 2) \frac{\to a + \to b}{∣ ∣ ∣ \to a + \to b ∣ ∣ ∣} = (\frac{4}{\sqrt{29}}, \frac{3}{\sqrt{29}}, \frac{- 2}{\sqrt{29}},)$

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Similar questions

Q. Two vectors

\to A

and

\to B

have magnitude

3

each. If

\to A \times \to B = - 5^k + 2^i

, then the angle between

A

and

B

Let $\to a$ and $\to b$ are vectors such that $| \to a + \to b | = \sqrt{29}$ and $\to a \times (2^i + 3^j + 4^k) = (2^i + 3^j + 4^k) \times \to b$ then $(\to a + \to b) . (- 7^i + 2^j + 3^k) =$

Q. Simplify:

\frac{3^{30} + 3^{29} + 3^{25}}{3^{31} + 3^{30} - 3^{29}} + \frac{2^{30} + 2^{29} + 2^{25}}{2^{31} + 2^{30} - 2^{29}}

Q. Two vectors

\to A

and

\to B

have magnitude

3

each.

\to A \times \to B = - 5^k + 2^i

. Find angle between

A

and

B

Find the reciprocal (or multiplicative inverse) of -2 + 5i

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The unit vector in the direction of the resultant of vectors →a=2^i+2^j−5^k and →b=2^i+^j+3^k is

The correct option is B →a+→b=(4,3,−2)→a+→b∣∣∣→a+→b∣∣∣=(4√29,3√29,−2√29,)

The unit vector in the direction of the resultant of vectors $\to a = 2^i + 2^j - 5^k a n d \to b = 2^i +^j + 3^k$ is

The correct option is B

$\to a + \to b = (4, 3, - 2) \frac{\to a + \to b}{∣ ∣ ∣ \to a + \to b ∣ ∣ ∣} = (\frac{4}{\sqrt{29}}, \frac{3}{\sqrt{29}}, \frac{- 2}{\sqrt{29}},)$