The units digit in the expression $(11^{1} + 12^{2} + 13^{3} + 14^{4} + 15^{5} + 16^{6})$ is

1

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9

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5

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4

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Solution

The correct option is B $9$
$\Rightarrow (11^{1} + 12^{2} + 13^{3} + 14^{4} + 15^{5} + 16^{6})$
in the following expression we take number that present on unit place
$1^{1} = 1 ∴ u n i t d i g i t = 1$
$2^{2} = 4 ∴ u n i t d i g i t = 4$
$3^{3} = 27 ∴ u n i t d i g i t = 7$
$4^{4} = 256 ∴ u n i t d i g i t = 6$
$5^{5} = 3125 ∴ u n i t d i g i t = 5$
$6^{6} = 46656 ∴ u n i t d i g i t = 6$
so $(1 + 4 + 7 + 6 + 5 + 6) = 29 ∴ u n i t d i g i t = 9$

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