The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. Find the number.
Let tens digit = x
Units digit = 3
∴ Number = 3 + 10x
According to the condition,
7 (x + 3) = 3 + 10x
7x + 21 = 3 + 10x
21 - 3 = 10x - 7x ⇒ 3x = 18
x=183=6
∴ Number = 3 + 10x
=3 + 10 × 6 = 3 + 60 = 63