The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself.Find the number
Unit digit of a two digit no = 3
Let digit at tens place be x
Two digit No. = 10 * tens place + 1 * ones place
= 10x+3
7(x + 3) =10x + 3
7x + 21 = 10x+3
21-3 = 10x-7x
x=18/3
x=6
Two digit no = 10*6+3
= 60+3
= 63