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Question

The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself.Find the number

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Solution

Unit digit of a two digit no = 3

Let digit at tens place be x

Two digit No. = 10 * tens place + 1 * ones place

= 10x+3

7(x + 3) =10x + 3

7x + 21 = 10x+3

21-3 = 10x-7x

x=18/3

x=6

Two digit no = 10*6+3

= 60+3

= 63


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