The units of solubility product of silver chromate $(A g_{2} C r O_{4})$ will be __________.

m o l^{2} L^{- 2}

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m o l^{3} L^{- 3}

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m o l L^{- 1}

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m o l L^{- 2}

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Solution

The correct option is C $m o l L^{- 1}$
Molar solubility is the number of moles of a substance (the solute) that can be dissolved per liter of solution before the solution becomes saturated. It can be calculated from a substance's solubility product constant (K_sp) and stoichiometry. The units are mol/L, sometimes written as M.

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