The universal gas constant has the units

dyne/

^{0} C

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erg/mole/k

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erg-cm/k

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watt/k

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Solution

The correct option is D erg/mole/k
from ideal gas equation, PV = nRT
now, the dimensions of PV is same as dimension of energy (or dimension of work)
So, dimension of PV is ergs
and the dimension of n is mol, dimension of T is Kelvin
So, dimension of R = $\frac{d i m e n s i o n o f P V}{d i m e n s i o n o f n \times d i m e n s i o n o f T e m p e r a t u r e}$
$= \frac{e r g}{m o l - K}$
so, B is the correct answer.

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Similar questions

8.3 J / m o l e / K

32 g m

- 73^{o} C

The Universal gas constant may be expressed as :

a) 8.31 J/mole-K c) 2.00 J/mole-K

b) 8.31 cal/mole-K d) 2.00 cal/mole-K

$N_{2}$	$O_{2}$	$C O_{2}$
$60$ %	$30$ %	$10$ %

8314 J / k m o l - K

0.082 l i t r e a t m m o l^{- 1} K^{- 1}

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