The universal set, ξ={x:1≤x≤15 and x is an integer}, set H={x:x is a multiple of 3} and set K={x:x is an even number}. find n(H′∩K)
Here ξ=1,2,3,...15
H={3,6,9,12,15}
K={2,4,6,8,10,12,14}
The Venn diagram is shown in the figure
Then the set (H′∩K) contains the elements contained in K but not common to H which is {2,4,8,10,14}.
∴n(H′∩K)=5