The unpaired electrons in $A l$ and $S i$ are present in $3 p - o r b i t a l$ . Which electron will experience more effective nuclear charge from the nucleus?

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Solution

Silicon has greater nuclear charge of $+ 14$ than Aluminium which has $+ 13$ nuclear change. Hence the unpaired $3 p$ electron in the silicon will experience more effective nuclear charge than Aluminium.
Effective nuclear charge in Silicon :- $14$ protons in the nucleus surrounded by $14$ electrons in which $10$ electrons shield the $^{'} 4 "$ valency electrons.
Hence effective nuclear charge is $+ 4$ . Effective nuclear charge in Aluminium :- $13$ protons in the nucleus surrounded by $13$ electrons. Hence the effective nuclear charge is $" 0 "$ as there is no shielding effect.

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The unpaired electrons in Al and Si are present in 3p−orbital. Which electron will experience more effective nuclear charge from the nucleus?

The unpaired electrons in $A l$ and $S i$ are present in $3 p - o r b i t a l$ . Which electron will experience more effective nuclear charge from the nucleus?