The correct option is C 2:3
Given that
Upper limit of the Class interval = 2a
Lower limit of the Class interval = a
We know that,
Class size = Upper limit of class interval - Lower limit of class interval.
= 2a - a
Class size = a
Mid value = 2a+a2=3a2
Ratio of class size and mid value a:3a2=2:3
Hence, option D is the correct answer.