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Question

The useful power produced by a reactor of 40% efficiency , in which 1014 fissions occuring each second and energy per fission in 275Mev, is

A
0.22Kw
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B
0.44kW
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C
0.88kW
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D
1.76kW
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Solution

The correct option is C 1.76kW
Energy produced per second =275×1014×106×1.6×1019 joules
=4400 joules

As, the reactor is only 40% efficient.
Power produced by the reaction =410×4400 joules/second
=1760 watt
=1.76 KW


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