Question

The v-s and $v^2$-s graph are given for two particles. Find the acceleration of the particles at s=0

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

1.

Equation of line is $(y-y_2)=\frac{y_2-y_1}{x_2-x_1}(x-x_2)$

$v=\frac{-2}{5}s+20$

$\frac{dv}{ds}=\frac{-2}{5}$

a = v $\frac{dv}{ds}ats=0v=20$

$\Rightarrow a=20\left(\frac{-2}{5}\right)=-8m/s^2$

2.

Equation of line

$v^2=\frac{-2}{5}s+20$

Differentiating with respect to s

2v $\frac{dv}{ds}=\frac{-2}{5}$

v $\frac{dv}{ds}=\frac{-1}{5}$

a = -0.2 m/$s^2$