The $v - t$ graph for a particle is as shown. The distance travelled in the first four seconds is

12 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

24 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $16 m$
$A r e a u n d e r v e l o c i t y t i m e g r a p h g i v e s u s t h e d i s p l a c e m e n t . T h u s a r e a o f r i g h t a n g l e t r i a n g l e = \frac{1}{2} b a s e \times a l t i d u e A r e a o f t r i a n g l e A = A r e a o f t r i a n g l e B = \frac{1}{2} \times 2 \times 8 = 8 m T h u s t o t a l a r e a o f t h e t r i a n g l e f o r m e d u n d e r 4 s e c = 16 m = d i s p l a c e m e n t$

Suggest Corrections

Similar questions

Time-velocity graph of a particle is shown in Fig.
(i) Calculate the distance travelled in first 8 seconds.

v - t

5

v = 3 - t

v = (3 - t) m / s

v = | t - 2 | m / s

t

Join BYJU'S Learning Program