The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?

Argon

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Vinyl chloride

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Carbon dioxide

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Methane

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Solution

The correct option is A Argon
The higher the value of $K_{H}$ , the lower is the solubility of the gas in the liquid. Hence the order of increasing solubility of the gases will be $A r < C O_{2} < C H_{4} < H C H O$

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The value for Henry’s constant for argon, carbon dioxide, methane and vinyl chloride at 298 K are 40.3 kbar, 1.67 kbar, 0.413 kbar and 0.611 kbar respectively. Which of the gas will be having least solubility?

The correct option is A ArgonThe higher the value of KH, the lower is the solubility of the gas in the liquid. Hence the order of increasing solubility of the gases will be Ar<CO2<CH4<HCHO

The correct option is A Argon
The higher the value of $K_{H}$ , the lower is the solubility of the gas in the liquid. Hence the order of increasing solubility of the gases will be $A r < C O_{2} < C H_{4} < H C H O$