The correct option is D 0.333....
Given operation is 0.111... + 0.222...
Let 'x' be 0.111....
Multilpy x with 10.
⇒ 10x = 1.11....
= 1 + 0.111....
= 1 + x (∵x=0.111....)
⇒ 9x = 1
⇒ x = 19
∴ 0.111.... = 19........................(1)
Now, 0.222... = 2 × 0.111....
∵ from (1), 0.111.... = 19
⇒0.222...=2×19
=29
∴0.111...+0.222...=19+29
=39
39=3×19
∵19=0.111..... [from eq(1)]
⇒39=3×0.111... =0.333....
∴0.111...+0.222...=0.333....