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Question

The value of 0.2log5(14+18+116+...) is


A

4

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B

log 4

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C

log 2

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D

log 2

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Solution

The correct option is A

4


We have,

14+18+116+.....=1/411/2=12

Hence,

0.2log5(14+18+116+...)=0.2log512

=(15)log512

=(51)2log512

=(5)2log512

=(5)log54

=4


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