1
Question
The value of 1.1!+2.2!+3.3!+..........+n.n!, is
The value of 1.1!+2.2!+3.3!+..........+n.n!, is
Open in App
Solution
The correct option is C (n+1)!−1
S=1.1!+2.2!.......................n.n! =(2−1)1!+(3−1)2!....................(n+1−1)n! =2.1!−1.1!+3.2!−2!................(n+1)n!−n! =2!−1!+3!−2!.........................(n+1)n!−n! =(n+1)!−1
S=1.1!+2.2!.......................n.n!
=(2−1)1!+(3−1)2!....................(n+1−1)n!
=2.1!−1.1!+3.2!−2!................(n+1)n!−n!
=2!−1!+3!−2!.........................(n+1)n!−n!
=(n+1)!−1
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
