Question

The value of $1-2\log 5+3\log 2$ is $\log \frac{16}{x}$.

Find $x$

Answer 1

$1-2\log 5+3\log 2$ ....(Assuming base 10)

$=\log 10-\log 5^2+\log 2^3$

$=\log \left(\frac{10\times 8}{25}\right)=\log \frac{16}{5}=\log 3.2$