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Derivative of Standard Functions

The value of ...

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The value of (1 + i)(1-i^2) (1+i^4)(1-i^5) is

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I^{n} = {I_{0}}^{π / 4} t a n^{n} X d x

\frac{1}{I_{2} + I_{4}} \frac{1}{I_{3} + I_{5}} \frac{1}{I_{5} + I_{6}}

Q. The value of

{(1 + i)}^{5} \times {(1 - i)}^{5}

Find the value of $∣ ∣ ∣ \begin{matrix} 2 + i & 2 - i 1 + i & 1 - i \end{matrix} ∣ ∣ ∣$ if $i^{2} = - 1$ .

The ionization potential values of an element are in the following order. The element is:

I_{1} < I_{2} <<<< I_{3} < I_{4} < I_{5}

I_{1} = \int_{1}^{2} \frac{d x}{\sqrt{1 + x^{2}}}

I_{2} = \int_{1}^{2} \frac{d x}{x}

then
compare value of

I_{1}

I_{2}

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