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Question

The value of (1+i)2002 is


A

a purely real number

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B

Purely imaginary number

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C

Has both real & imaginary parts

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D

None of these

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Solution

The correct option is B

Purely imaginary number


(1+i)2002 = [(1+i)2]1001 = [2i]1001

21001 . i1001

= i.21001


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