The correct option is D 0 (1+w+√(w))(1+w √(w)) =(1+w)^2 w =1+w^2+2w w =1+w+w^2 =0 ...

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Definite Integral as Limit of Sum

The value of ...

Question

The value of $(1 + \sqrt{ω} + ω) (1 - \sqrt{ω} + ω) =$

0

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ω

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ω^{2}

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Solution

The correct option is D $0$
$(1 + w + \sqrt{w}) (1 + w - \sqrt{w})$
$= (1 + w)^{2} - w$
$= 1 + w^{2} + 2 w - w$
$= 1 + w + w^{2}$
$= 0$

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