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Byju's Answer
Standard XI
Mathematics
Integration to solve modified sum of binomial coefficients
The value of ...
Question
The value of
(
1
+
√
2
)
7
+
(
1
−
√
2
)
7
is
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Solution
We know that,
(
1
+
x
)
n
+
(
1
−
x
)
n
=
2
(
n
C
0
+
n
C
2
x
2
+
n
C
4
x
4
+
⋯
)
So,
(
1
+
√
2
)
7
+
(
1
−
√
2
)
7
=
2
(
7
C
0
+
7
C
2
(
√
2
)
2
+
7
C
4
(
√
2
)
4
+
7
C
6
(
√
2
)
6
)
=
2
(
1
+
42
+
140
+
56
)
=
478
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Integration to solve modified sum of binomial coefficients
Standard XI Mathematics
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