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B
222
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C
223
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D
224
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Solution
The correct option is C223 We know that, tan(A+B)=tanA+tanB1−tanAtanB Assuming A+B=45∘ tanA+tanB=1−tanAtanB⇒tanA+1+tanB(tanA+1)=2 ⇒(1+tanA)(1+tanB)=2 Now, (1+tan1∘)(1+tan2∘)…(1+tan45∘)=(1+tan1∘)(1+tan44∘)(1+tan2∘)(1+tan43∘)…(1+tan45∘)=223