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Question

The value of (1+tan1o)(1+tan2o)(1+tan3o)............(1+tan45o) is equal to

A
221
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B
222
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C
223
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D
224
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Solution

The correct option is C 223
As we know that,
(1+tanx)(1+tan(45x))=(1+tan)(1+tan45tanx1+tan45tanx)

=(1+tanx)(1+tanx+1tanx1+tanx)

=2

(1+tan1)(1+tan2)(1+tan3)............(1+tan45)

=(1+tan1)(1+tan44)(1+tan2)(1+tan43)......(1+tan45)

=(1+tan1)(1+tan(451))(1+tan2)(1+tan(452)).......(1+1)

=2×2×....upto 22 times ×2

=222×2=223

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