The value of -109-2 is -11881-10881-11880-11891-

The correct option is A 11881 109 = 100 + 9 Using the identity: (a+b)^2= (a)^2+2 × a nbsp;× b+(b)^2, (100+9)^2=(100)^2+2 × 100 × 9+(9)^2 =10000+1800+81 = 11 ...

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Standard VIII

Mathematics

The value of ...

Question

The value of $(109)^{2}$ is _______.

11881

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10881

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11891

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11880

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Solution

The correct option is A
11881

$109 = 100 + 9$

Using the identity:
$(a + b)^{2}$ = $(a)^{2} + 2 \times a \times b + (b)^{2}$ ,
$(100 + 9)^{2} = (100)^{2} + 2 \times 100 \times 9 + (9)^{2}$
$= 10000 + 1800 + 81$
$= 11881$

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Standard VIII Mathematics

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The value of (109)2 is _______.

The correct option is A 11881 109=100+9 Using the identity: (a+b)2= (a)2+2×a×b+(b)2, (100+9)2=(100)2+2×100×9+(9)2 =10000+1800+81 =11881

The value of $(109)^{2}$ is _______.

The correct option is A
11881

$109 = 100 + 9$

Using the identity:
$(a + b)^{2}$ = $(a)^{2} + 2 \times a \times b + (b)^{2}$ ,
$(100 + 9)^{2} = (100)^{2} + 2 \times 100 \times 9 + (9)^{2}$
$= 10000 + 1800 + 81$
$= 11881$