Question

The value of $10n$ in the expression
$\frac{n}{4}-5=\frac{1}{2}\left(\frac{n}{6}-2\right)+\left(\frac{7n-2}{2}\right)$ is___________

Answer 1

$\frac{n}{4}-5=\frac{1}{2}\left(\frac{n}{6}-2\right)+\left(\frac{7n-2}{2}\right)$

$\Rightarrow \frac{n-20}{4}=\frac{1}{2}\left(\frac{n-12}{6}\right)+\frac{1}{2}\left(\frac{6(7n-2)}{6}\right)$

$\Rightarrow \frac{n-20}{4}=\frac{n-12+42n-12}{12}$

$\Rightarrow \frac{n-20}{4}=\frac{43n-44}{12}$

$\Rightarrow 3n-60=43n-44$

$\Rightarrow -16=40n$

$\Rightarrow n=\frac{-16}{40}=-\frac{4}{10}=-0.4$

$10n=-4$