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Question

The value of 12C2+13C3+14C4+........+999C989 is

A
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B
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C
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D
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Solution

The correct option is A
Since 10C0+11C1+12C2+13C3+.........+999C989
=1000C989=1000C11
(Since,10C0=11C0 and nCr+nCr1=n+1Cr)
So, 12C2+13C3+14C4+......+999C989=1000C1112

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