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B
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C
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D
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Solution
The correct option is A Since10C0+11C1+12C2+13C3+.........+999C989 =1000C989=1000C11 (Since,10C0=11C0andnCr+nCr−1=n+1Cr) So,12C2+13C3+14C4+......+999C989=1000C11−12