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B
5.4267
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C
5.5267
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D
5.001
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Solution
The correct option is A5.0267 (127)1/3=(125+2)1/3 Let y=f(x)=x1/3 y+Δy=(x+Δx)1/3 ⇒Δy=(x+Δx)1/3−x1/3 Also, Δy=f′(x)Δx ⇒(x+Δx)1/3−x1/3=13x−2/3Δx Put x=125,Δx=2 ⇒(127)1/3−5=13(5)−2(2) ⇒(127)1/3=5+0.0267=5.0267