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Question

The value of 15C20 15C21+ 15C22 15C215 is

A
15
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B
15
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C
0
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D
51
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Solution

The correct option is C 0
Let f(n)=C20C21+C22C23++(1)n C2n
We know that
f(n)={0 ,if n is odd(1)n/2 Cn/2 ,if n is even

Since, here n is odd (n=15)
15C20 15C21+ 15C22 15C215=0

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