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Multiplying Exponents with Different Base but Same Exponent

The value of ...

Question

The value of ${((2)^{- 1})}^{- 2}$ is .

A

4^{- 2}

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B

16

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C

4

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D

\frac{1}{4}

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Solution

The correct option is C 4
Note that $(a^{m})^{n} = a^{m n}$
$⟹ {((2)^{- 1})}^{- 2}$ = $(2)^{2}$ = 4

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