The value of $(2^{2})^{2} + (3^{2})^{2}$ =.

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Solution

The correct option is A 97
By a law of exponents , we know that $(a^{m})^{n} = a^{m n} .$
$⟹$ $(2^{2})^{2} = 2^{4} = 16$ and $(3^{2})^{2} = 3^{4} = 81$
$⟹$ $(2^{2})^{2} + (3^{2})^{2} = 16 + 81 = 97$

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