The value of $[4^{- 1} + 3^{- 1} + 6^{- 2}]^{- 1}$ is ___.

$\frac{36}{22}$

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$\frac{38}{22}$

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$\frac{36}{20}$

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$\frac{36}{11}$

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Solution

The correct option is A
$\frac{36}{22}$

$[4^{- 1} + 3^{- 1} + 6^{- 2}]^{- 1}$ = { $\frac{1}{4}$ + $\frac{1}{3}$ + $\frac{1}{36}$ } ^ -1

The value of $[4^{- 1} + 3^{- 1} + 6^{- 2}]^{- 1}$ is $\frac{36}{22}$

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