The correct option is B 4096 (2^6)^2 = 2^6× 2 #160; #160; #160; #160; #160; #160; #160; #160; #160; [ By using (a ...

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Byju's Answer

Standard VII

Mathematics

Power of a Power

The value of ...

Question

The value of $(2^{6})^{2}$ is

256

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4096

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1028

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512

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Solution

The correct option is B $4096$
$(2^{6})^{2} = 2^{6 \times 2}$ $[$ By using $(a^{m})^{n} = a^{m \times n}]$
$= 2^{12}$
$= 4096$

So, option $B$ is correct.

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Similar questions

Q. If

4096^{\frac{x}{4}} = 512

, find the value of

x

Q. Is

512

a term of the sequence

1 / 256, 1 / 64, 1 / 16

______?

The following table gives some of the powers of 2.

Can you compute the products using the table.

2¹	2	2⁶	64	2¹¹	2048
2²	4	2⁷	128	2¹²	4096
2³	8	2⁸	256	2¹³	8192
2⁴	16	2⁹	512	2¹⁴	16384
2⁵	32	2¹⁰	1024	2¹⁵	32768

(i) 16 × 64

(ii) 32 × 512

(iii) 64 × 256

(iv) 128 × 256

Question 7
The lateral surface area of a cube is $256 m^{2}$ . The volume of the cube is:

A) $512 m^{3}$
B) $64 m^{3}$
C) $216 m^{3}$
D) $256 m^{3}$

Q. Choose the correct alternative in the following question:

If 2^{n} = 4096, then 2^{n - 5} = (a) 128 (b) 64 (c) 256 (d) 32

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The value of (26)2 is

The correct option is B 4096(26)2=26×2 [By using (am)n=am×n] =212 =4096So, option B is correct.

The value of $(2^{6})^{2}$ is

The correct option is B $4096$
$(2^{6})^{2} = 2^{6 \times 2}$ $[$ By using $(a^{m})^{n} = a^{m \times n}]$
$= 2^{12}$
$= 4096$

So, option $B$ is correct.