Question

The value of $2\log 9-\log 18$ is equal to

• A. $\log 9$
• B. $-\log 9$
• C. $\log 4.5$
• D. $-\log 4.5$

Answer 1

The correct option is C $\log 4.5$

$2\log 9-\log 18=\log 9^2-\log 18$

$=\log \left(\frac{9\times 9}{18}\right)=\log \left(\frac{9}{2}\right)$ $(\because \log \left(\frac{a}{b}\right)=\log a-\log b)$

$=\log 4.5$