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Question

The value of 2n{1.3.5.....(2n−3)(2n−1)} is


A

(2n)!n!

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B

(2n)!2n

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C

n!(2n)!

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D

(2n1)!n!

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Solution

The correct option is A

(2n)!n!


1.3.5......(2n1)2n = 1.2.3.4.5.6....(2n1)(2n)2n2.4.5.....2n

= (2n)!2n2n(1.2.3......n) = (2n)!n!


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