The value of 2 sin 23 -5-2 cos 22 -5-2 2-3 is

2sin^23π5+2cos^22π5+2^2π3 =2sin^2(π 2π5)+2cos^22π5+2^2π3 =2(sin^22π5+cos^22π5)+2(2)^2 =2+8=10 ...

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Sign of Trigonometric Ratios in Different Quadrants

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The value of $2 {sin}^{2} \frac{3 π}{5} + 2 {cos}^{2} \frac{2 π}{5} + 2 {sec}^{2} \frac{π}{3}$ is

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2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

Prove that:

$2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10$

2 {sin}^{2} \frac{3 π}{4} + 2 {cos}^{2} \frac{π}{4} + 2 {sec}^{2} \frac{π}{3} = 10

a n t i {log}_{5} ⎡ ⎢ ⎢ ⎣ \frac{{tan}^{2} (\frac{π}{5}) + {tan}^{2} (\frac{2 π}{5}) + 20}{{cot}^{2} (\frac{π}{5}) + {cot}^{2} (\frac{2 π}{5}) + 28} ⎤ ⎥ ⎥ ⎦

{cot}^{2} \frac{π}{9} + {cot}^{2} \frac{2 π}{9} + {cot}^{2} \frac{4 π}{9}

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