The value of 2tan260- - 4cos245- - 3230- is

The correct option is D 0 #160; #160; 2tan^260^∘ 4cos^245^∘ 3^230^∘ =2(√(3))^2 4(1√(2))^2 3(2√(3))^2 =2(3) 42 4 =6 2 4 = ...

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The value of $2 {tan}^{2} 60^{\circ} - 4 {cos}^{2} 45^{\circ} - 3 {sec}^{2} 30^{\circ}$ is

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Evaluate each of the following

$\frac{t a n^{2} 60^{o} + 4 c o s^{2} 45^{o} + 3 s e c^{2} 30^{o} + 5 c o s^{2} 90^{o}}{c o s e c 30^{o} + s e c 60^{o} - c o t^{2} 30^{o}}$

\frac{{tan}^{2} 60^{\circ} + 4 {cos}^{2} 45^{\circ} + 3 {sec}^{2} 30^{\circ} + 5 {cos}^{2} 90^{\circ}}{c o s e c 30^{\circ} + sec 60^{\circ} - {cot}^{2} 30^{\circ}}

\frac{\tan^{2} 60 ° + 4 \cos^{2} 45 ° + 3 \sec^{2} 30 ° + 5 \cos^{2} 90 °}{cosec 30 ° + \sec 60 ° - \cot^{2} 30 °}

\frac{{tan}^{2} 60^{\circ} + 4 {cos}^{2} 45^{\circ} + 3 {sec}^{2} 30^{\circ} + 5 {cos}^{2} 90^{\circ}}{cosec 30^{\circ} + sec 60^{\circ} - {cot}^{2} 30^{\circ}}

\frac{4}{3} {cot}^{2} 30^{\circ} + 3 {sin}^{2} 60^{\circ} - 2 {c o s e c}^{2} 60^{\circ} + \frac{3}{4} {tan}^{2} 30^{\circ}

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