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Question

The value of 2×2sin2π6+2cosec27π6cos2π3

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Solution

2×2sin2π6+2cosec27π6cos2π3

=2×2(12)2+2×cosec2(π+π6)(12)2

=1+2×[cosec(π6)]2×14

=1+(2)2×12

=1+2=3

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