The correct option is C 20!⋅61C21
20!+21!1!+22!2!+.....+60!40!
=20!(20!0!×20!+21!1!⋅20!+22!2!×20!+.....+60!40!×20!)
=20!(20C0+21C1+22C2+....+60C40)
=20!(21C0+21C1+22C2+....+60C40)
We know that,
(21C0+21C1)=22C1
(22C1+22C2)=23C2 and so on
.
.
.
so,
(60C39+60C40)=61C40=61C21
Hence the value of the sum is,
20!⋅61C21