The value of 23 - 222-3 - 150 -291-22- is 196289324400

The correct option is D 400 {(23 + 2^2)^2/3 + (150 29)^1/2}^2 = [(23 +4)^2/3+(121)^1/2]^2 = [(27)^2/3+(121)^1/2]^2 = [(3^3)^2/3+(11^2)^1/2]^2=(9 + 11)^2 = ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

The value of ...

Question

The value of ${(23 + 2^{2})^{\frac{2}{3}} + (150 - 29)^{\frac{1}{2}}}^{2}$ , is

196

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289

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324

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400

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Solution

The correct option is D
400

${(23 + 2^{2})^{\frac{2}{3}} + (150 - 29)^{\frac{1}{2}}}^{2} = [(23 + 4)^{\frac{2}{3}} + (121)^{\frac{1}{2}}]^{2} = [(27)^{\frac{2}{3}} + (121)^{\frac{1}{2}}]^{2} = [(3^{3})^{\frac{2}{3}} + (11^{2})^{\frac{1}{2}}]^{2} = (9 + 11)^{2} = (20)^{2} = 400$

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Similar questions

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The value of {(23+22)23+(150−29)12}2, is

The correct option is D 400 {(23+22)23+(150−29)12}2=[(23+4)23+(121)12]2=[(27)23+(121)12]2=[(33)23+(112)12]2=(9+11)2=(20)2=400

The value of ${(23 + 2^{2})^{\frac{2}{3}} + (150 - 29)^{\frac{1}{2}}}^{2}$ , is

The correct option is D
400

${(23 + 2^{2})^{\frac{2}{3}} + (150 - 29)^{\frac{1}{2}}}^{2} = [(23 + 4)^{\frac{2}{3}} + (121)^{\frac{1}{2}}]^{2} = [(27)^{\frac{2}{3}} + (121)^{\frac{1}{2}}]^{2} = [(3^{3})^{\frac{2}{3}} + (11^{2})^{\frac{1}{2}}]^{2} = (9 + 11)^{2} = (20)^{2} = 400$