The value of $25 x^{2} + 16 y^{2} + 40 x y$ at $x = 1$ and $y = - 1$ is

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-49

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none of these

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Solution

The correct option is D 1
The value of $25 x^{2} + 16 y^{2} + 40 x y$ at $x = 1$ and $y = - 1$ is
$25 (1)^{2} + 16 (- 1)^{2} + 40 (1) (- 1)$
$\Rightarrow 25 + 16 - 40$
$\Rightarrow 1$
$\Rightarrow$ Option C is correct.

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x = \frac{1}{4}, y = \frac{1}{5}

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