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Question

The value of (2a2b−3c3)(3a3b+4c) is

A
5a6b2+12c49a3bc312c4
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B
5a5b2+8a2bc9a3bc3+12c4
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C
6a5b2+8a2bc9a3bc3+12c4
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D
6a6b2+8a2bc9a3bc312c4
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E
6a5b2+8a2bc9a3bc312c4
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Solution

The correct option is E 6a5b2+8a2bc9a3bc312c4
The value of (2a2b3c3)(3a3b+4c)
=2a2b(3a3b+4c)3c3(3a3b+4c)
=6a5b2+8a2bc9a3c3b12c4

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