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Question

The value of 2sec1 2+sin1(12) is

(a) π6 (b) 5π6 (c) 7π6 (d) 1

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Solution

(b) We have,2 sec1 2+sin112=2sec1( secπ3)+sin1( sinπ6)

=2.π3+π6 [ sec1(sec x)=x and sin1(sin x)=x]=4π+π6=5π6


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