The value of (2x+3y)3 is __________.
8x3+27y3+36x2y+54xy2
8x3−27y2−36x2y+54xy2
8x3+36y3+36x2y+54xy2
18x3+27y3+36x2y+54xy2
We know the identity, (a+b)3=a3+b3+3a2b+3ab2
(2x+3y)3=(2x)3+(3y)3+3(2x)2×(3y)+3×(2x)×(3y)2
= 8x3+27y3+36x2y+54xy2