The value of (2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=
A
27x3
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B
29x3+(x+3y)3
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C
(2x−3y)3+(x+3y)3
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D
0
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Solution
The correct option is A27x3 Substitute 2x−3y=a and (x+3y)=b (2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2 =a3+b3+3a2b+3ab2 =(a+b)3 =(2x−3y+x+3y)3 =(3x)3 =27x3