The value of 30 - 40 - 52 is

The correct option is B 0 To find the value of #160; (3^0 4^0) × 5^2 (3^0 #160; #160;4^0) × 5^2 = (1 1) × 25 = 0×25 = ...

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Byju's Answer

Standard IX

Mathematics

Laws of Exponents for Real Numbers

The value of ...

Question

The value of $(3^{0} - 4^{0}) \times 5^{2}$ is

25

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0

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- 25

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none of these

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Solution

The correct option is B $0$
To find the value of $(3^{0} - 4^{0}) \times 5^{2}$

$(3^{0} - 4^{0}) \times 5^{2}$
$= (1 - 1) \times 25$
$= 0 \times 25$
$= 0$

Hence, the value is $0$

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Similar questions

Which of the following shows the correct histogram for the given data:
$\begin{matrix} Class interval & 20 - 25 & 25 - 30 & 30 - 35 & 35 - 40 & 40 - 45 & 45 - 50 Frequency & 30 & 24 & 52 & 28 & 46 & 100 \end{matrix}$

Draw a histogram and the frequency polygon from the following data:
$\begin{matrix} Class interval & 20 - 25 & 25 - 30 & 30 - 35 & 35 - 40 & 40 - 45 & 45 - 50 Frequency & 30 & 24 & 52 & 28 & 46 & 100 \end{matrix}$

Q. If

f (x) = \{\begin{matrix} \frac{1 - \cos 10 x}{x^{2}}, & x < 0 \\ a, & x = 0 \\ \frac{\sqrt{x}}{\sqrt{625 + \sqrt{x}} - 25}, & x > 0 \end{matrix}

then the value of a so that f (x) may be continuous at x = 0, is
(a) 25
(b) 50
(c) −25
(d) none of these

(\frac{30 \times 25}{60 \times 5})^{2}

= ?

Find the value of $2^{5} \times 5^{2}$ .

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The value of (30−40)×52 is

The correct option is B 0To find the value of (30−40)×52(30−40)×52=(1−1)×25=0×25=0Hence, the value is 0

The value of $(3^{0} - 4^{0}) \times 5^{2}$ is

The correct option is B $0$
To find the value of $(3^{0} - 4^{0}) \times 5^{2}$

$(3^{0} - 4^{0}) \times 5^{2}$
$= (1 - 1) \times 25$
$= 0 \times 25$
$= 0$

Hence, the value is $0$