The value of $({(32)^{- 1})}^{- 2}$ is

(32)^{- 3}

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(32)^{- 2}

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(32)^{3}

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(32)^{2}

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Solution

The correct option is D $(32)^{2}$
We know, $(a^{m})^{n} = a^{m n}$ for a non-zero integer $a$ and any integers $m$ and $n .$

$\Rightarrow ({(32)^{- 1})}^{- 2} = {(32)}^{- 1 \times - 2}$
$= (32)^{2}$

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