The value of -3-2- 6-4-2- 4 is equal to

The correct option is B 48 [(3+2)× (6 4)+2]× 4 #160; (3+2)=5 and #160; (6 4)=2 ∴ [5× 2+2]× 4 = #160; [10+2]× 4 =12× 4 ...

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The value of ...

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The value of $[(3 + 2) \times (6 - 4) + 2] \times 4$ is equal to

48

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42

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46

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45

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(3 + 2) \times (6 - 4)

40

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{(4 p q + 3 q)}^{2} - {(4 p q - 3 q)}^{2} =

\frac{1}{1 \cdot 2 \cdot 3} + \frac{1}{2 \cdot 3 \cdot 4} + \frac{1}{3 \cdot 4 \cdot 5} + \frac{1}{4 \cdot 5 \cdot 6}

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