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B
264
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C
121
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D
343
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Solution
The correct option is A 252 In the identity ,(a+b+c)(a2+b2+c2−ab−bc−ca) = a3+b3+c3−3abc , if (a+b+c) = 0 , then a3+b3+c3=3abc. Since, (-3)+(-4)+(7) = 0. Hence, (-3)3 + (7)3 + (-4)3 = 3(-3)(-4)(7) = 252.