Question

The value of $3\frac{1}{12}-[1\frac{3}{4}+\{2\frac{1}{2}-(1\frac{1}{2}-\frac{1}{3})\}]$ is ________ .

• A. $\frac{1}{2}$
• B. $2$
• C. $1$
• D. $0$

Answer 1

The correct option is D $0$

The value of

$3\frac{1}{12}-[1\frac{3}{4}+\{2\frac{1}{2}-(1\frac{1}{2}-\frac{1}{3})\}]=\frac{37}{12}-[\frac{7}{4}+\{\frac{5}{2}-(\frac{3}{2}-\frac{1}{3})\}]=\frac{37}{12}-[\frac{7}{4}+\{\frac{5}{2}-\left(\frac{9-2}{6}\right)\}]=\frac{37}{12}-[\frac{7}{4}+\{\frac{5}{2}-\frac{7}{6}\}]=\frac{37}{12}-[\frac{7}{4}+\left\{\frac{15-7}{6}\right\}]=\frac{37}{12}-[\frac{7}{4}+\frac{8}{6}]=\frac{37}{12}-\left[\frac{21+16}{12}\right]=\frac{37}{12}-\frac{37}{12}=0$